A volume of 8 liters of gas has a pressure of 50 kPa and a temp of 27^{o}C.

a) If the pressure were increased to 300 kPa without changing he temperature
what would be the resulting volume? b) If the temperature was raised to 627^{o} C while maintaining
the original pressure, what would be the final volume? c) What would be the resulting volume
if the temperature was raised to 627^{o}C and the pressure increased to 300 kPa simultaneously?

Hint 1

If the temperature is constant, then pressure is inversely proportional to
the volume ( Boyle's Law) that is P a 1/V or PV = constant

b) If the pressure is kept constant, then volume is directly proportional
to temperature (Charle's Law) that is V a T or V/T = constant

Answer 1

V_{1} = 8 liters

P_{1} = 50 kPa

T_{1} = 27^{o} C = 300 K

If the temperature is constant, then pressure is inversely proportional to
the volume ( Boyle's Law) that is P a 1/V or PV = constant

P_{1}V_{1} = P_{2}V_{2}

P_{2} = 300 kPa

50 x 10^{3} x 8 = 300 x 10^{3} x V_{2}

V_{2} = (50 x 10^{3} x 8)/(300 x 10^{3}) = 1.33 liters

b) If the pressure is kept constant, then volume is directly proportional to temperature (Charle's Law) that is V a T or V/T = constant