Work

Energy

Power Work

done Cases where

work is

not done Positive

and

Negative Work Examples

on

Work Done Work with

Variable

Force Work by

Variable

Force Q&A

Energy

Power Work

done Cases where

work is

not done Positive

and

Negative Work Examples

on

Work Done Work with

Variable

Force Work by

Variable

Force Q&A

A force F = 2x + 5 acts on a particle. Find the work done by the force during the displacement of the particle from x =0m to x = 2m. Given that the force is in Newtons.

Work done W = ∫F(x)dx

Thus W = = ∫F(x)dx Cos 0^{o}

= ∫F(x)dx

= ∫(2x + 5)dx

= 2x^{2}/2 + 5x |

= 2^{2} + 5 x 2

= 14 J